X^2+8x+40=20

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Solution for X^2+8x+40=20 equation: 



X^2+8X+40=20

We move all terms to the left:

X^2+8X+40-(20)=0

We add all the numbers together, and all the variables

X^2+8X+20=0

a = 1; b = 8; c = +20;
Δ = b2-4ac
Δ = 82-4·1·20
Δ = -16
Delta is less than zero, so there is no solution for the equation

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